1.

Lists I, II and III contains conics, equation of tangents to the conics and points of contact, respectively. For a=sqrt2 if a tangent is drawn to a suitable conic (List I) at the point of contact (-1,1), which of the following options is the only CORRECT combination for obtaining its equation?

Answer»

(II) (ii) (Q)
(III) (i) (P)
(I) (i) (P)
(I) (ii) (Q)

Solution :For `a=sqrt2` and POINT `(-1,1)` on the CURVE, the only possible curve is `x^(2)+y^(2)=a^(2)`
Equation of tangent is `y=mx+asqrt(m^(2)+1)` and point of CONTACT is `((-ma)/(sqrt(x^(2)+1)),(a)/(sqrt(m^(2)+1)))`.


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