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Lithium borohydribe, LiBH_4, crystallizes in an orthorhombic system with 4 molecules per unit cell. The unit cell dimensions are : a=6.81 Å, b=4.43 Å and c=7.17 Å.Calculate the density of the crystal. Take atomic mass of Li=7, B=11 and H=1 a.m.u. |
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Answer» Solution :Molar MASS of `LiBH_4`=7+11+4=22 g `mol^(-1)` Mass of the UNIT cell =`(4xx22 "g mol"^(-1))/(6.02xx10^23 "mol"^(-1))=14.62xx10^(-23)g` Volume of the unit cell = a X b x c =`(6.81xx10^(-8) cm)(4.43xx10^(-8)cm) (7.17xx10^(-8)cm) =21.63xx10^(-23) cm^3` `THEREFORE` Density of the unit cell =`"Mass"/"Volume"=(14.62xx10^(-23)g)/(21.63xx10^(-23) cm^2)=0.676 g cm^(-3)` |
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