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Lithium forms body centred cube structure .The length of the side of its unirt cell is 351 pm Atomic radius of the lithium will beA. 240.8 pmB. 151.8 pmC. 75.5 pmD. 300.5 pm |
Answer» Correct Answer - B In case of body centred cubic (bcc) crystal, `asqrt3=4r` Given, edge length, a=351 pm Hence, atomic radius of lithium, `r=(asqrt3)/(4)=(351xx1.732)/(4)` `=151.98" pm"` |
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