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Lithium forms body centred cubic structure. The length of the side of its unit cell is 351 pm. Atomic radius of the lithium will be. |
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Answer» 300 pm For BCC unit cell, `a SQRT(3)=4r` `r=(a sqrt(3))/(4)=(351xxsqrt(3))/(4)=152` pm Thus neglecting `a//v^(2)` GIVES `P(V-b)=RT` or `PV=RT+Pb` or `(PV)/(RT)=Z=(RT+Pb)/(RT)rArr Z=1+Pb//RT` |
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