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Lithium has a bcc structure .Its density is `530 kg m^(-3)` and its atomic mass is `6.94 g mol^(-1)` .Calculate the edge length of a unit cell of lithium metal `(N_(A) = 6.02 xx 10^(23) mol^(-1))`A. 154pmB. 352pmC. 527pmD. 264pm |
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Answer» Correct Answer - B `rho=(ZxxM)/(N_(A)xxa^(3))` For bcc structure `Z=2.rho=530kg m^(-3)=0.530 g cm^(-1)` `0.530=(2xx6.94)/(6.02xx10^(23)xxa^(3))` `a^(3)=4.348xx10^(-23)cm^(3)` `a=3.52xx10^(-8)`cm a=352pm |
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