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LL A presbyopic patient has near point as 30 cmand far point as 40 cm. The dioptric power forthe corrective lens for seeing near object is​

Answer» ONG>EXPLANATION:

far point (f)=-40

power of lens=reciprocal of its focal length

p=1/f

according to the formula E,

p=1/-40=-2.5D

so the answer is -2.5D



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