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匕o.ynno le, af Gilucofeu.is,

Answer»

MW of glucose 180.2

The mass of 1

mol= 180.2 g + 1000g solvent 1180.2 g

The mass o 0.2 mol = 180 x 0.2 = 36 g

the mass of solution of 0.2 molality = 1036 g

We Will have 0.2 molality in 10036 g of the given solution

36 g/ 180.2 = 0.2 mol

And 1000 g of solvent = 0.2 mol/1 kg



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