1.

Load-elongation graphs of two wires A and B, made of the same material and of equal initial length are shown in the fig.1.21. Which wire is thicker?

Answer»

Solution :`Y=(FL)/(al)`
or, `a=(FL)/(YL)` (a= area of CROSS section of the wires)
F,L and Y are the same for the TWO wires,
`therefore a prop 1/l`
So the wire of SMALLER elongation has a LARGER cross section.
`therefore (a)_A gt (a)_B`
Hence , the wire A is thicker than the wire B.


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