1.

Locate `sqrt(2)`on the number line.

Answer» `sqrt2 = sqrt(1+1)`
`2 = 1+1`
`(sqrt2)^2 = (1)^2 + (1)^2`
`(sqrt2)^2` is taken as hypotenuse
with centre as O, we can make a triangle and locate `sqrt2`
OA & OC will be the radii of the circle


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