InterviewSolution
Saved Bookmarks
| 1. |
Locate `sqrt(2)`on the number line. |
|
Answer» `sqrt2 = sqrt(1+1)` `2 = 1+1` `(sqrt2)^2 = (1)^2 + (1)^2` `(sqrt2)^2` is taken as hypotenuse with centre as O, we can make a triangle and locate `sqrt2` OA & OC will be the radii of the circle |
|