1.

Locate `sqrt10 and sqrt17` on number line.

Answer» We can write,
`(sqrt10)^2 = 3^2+1^2`
So, we can create a right angle triangle with these three values.
On number line, at number `3`, we can create a perpendicular of `1` unit and then, from `0`, we can create an arc to top of perpendicular.
Point that the arc will cut on number line will be `sqrt10`.

`(sqrt17)^2 = 4^2+1^2`
So, we can create a right angle triangle with these three values.
On number line, at number `4`, we can create a perpendicular of `1` unit and then, from `0`, we can create an arc to top of perpendicular.
Point that the arc will cut on number line will be `sqrt17`.
Please refer to video to see the location on number line.


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