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Locate `sqrt10 and sqrt17` on number line. |
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Answer» We can write, `(sqrt10)^2 = 3^2+1^2` So, we can create a right angle triangle with these three values. On number line, at number `3`, we can create a perpendicular of `1` unit and then, from `0`, we can create an arc to top of perpendicular. Point that the arc will cut on number line will be `sqrt10`. `(sqrt17)^2 = 4^2+1^2` So, we can create a right angle triangle with these three values. On number line, at number `4`, we can create a perpendicular of `1` unit and then, from `0`, we can create an arc to top of perpendicular. Point that the arc will cut on number line will be `sqrt17`. Please refer to video to see the location on number line. |
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