1.

Locus of feet of perpendicular from (5,0) to the tangents of (x^(2))/(16)-y^(2)/(9)=1 is

Answer»

`x^(2)+y^(2)=4`
`x^(2)+y^(2)=16`
`x^(2)+y^(2)=9`
`x^(2)+y^(2)=25`

ANSWER :B


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