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Locus of midpoint of chord of circle x^(2)+y^(2)=1 which subtend right angle at (2,-1) is |
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Answer» `X^(2)+y^(2)-2x+y-2=0` `AP=PC` `AP^(2)=PC^(2)` `AP^(2)=(H-2)^(2)+(k+1)^(2)` `(1)^(2)-(h^(2)+k^(2))=h^(2)+k^(2)-4h+2k+5` `implies2x^(2)+2Y^(2)-4x+2y+4=0` `x^(2)+y^(2)-2x+y+2=0` |
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