1.

Locus of midpoint of chord of circle x^(2)+y^(2)=1 which subtend right angle at (2,-1) is

Answer»

`X^(2)+y^(2)-2x+y-2=0`
`x^(2)+y^(2)-2x-y-2=0`
`x^(2)+y^(2)-2x+y+1=0`
`x^(2)+y^(2)-2x+y+2=0`

SOLUTION :
`AP=PC`
`AP^(2)=PC^(2)`
`AP^(2)=(H-2)^(2)+(k+1)^(2)`
`(1)^(2)-(h^(2)+k^(2))=h^(2)+k^(2)-4h+2k+5`
`implies2x^(2)+2Y^(2)-4x+2y+4=0`
`x^(2)+y^(2)-2x+y+2=0`


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