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Locus of the feet of the perpendiculars drawn from either foci on a variable tangent to the hyperbola `16y^2 -9 x^2 = 1` isA. `x^(2)+y^(2)=9`B. `x^(2)+y^(2)=1//9`C. `x^(2)+y^(2)=7//144`D. `x^(2)+y^(2)=1//16` |
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Answer» Correct Answer - D `(y^(2))/(1//16)-(x^(2))/(1//9)=1` Locus will be the auxiliary circle `x^(2)+y^(2)=(1)/(16)` |
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