1.

Locus of the point P if AP2−BP2=18, where A ≡ (1, 2, –3) and B ≡ (3, –2, 1) is .

Answer»

Locus of the point P if AP2BP2=18, where A ≡ (1, 2, –3) and B ≡ (3, –2, 1) is .



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