log, 343IWBSC3 log 1 728log logIv – InterviewSolution

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1.

log, 343IWBSC3 log 1 728log logIv

Answer»

3log1728 = 3log(12)³ = 9log12

and 1/2*(log36) + 1/3*(log8) = log(36)½ + log(8)⅓ = log6+log2 = log(12)

now putting this back in the equation

1/6*(9log12/log12)^½= 1/6*(9)½= 3/6 = 1/2.

please post clear Images from next time.

thanks

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