1.

\log x+\log (x-5)=\log 6

Answer»

log x + log (x-5) = log 6 log x(x-5) = log 6So, x(x-5) = 6 x² - 5x - 6 = 0x² + x - 6x - 6 = 0 x(x+1) -6(x+1) = 0 (x+1)(x-6) = 0x = 6 , - 1ignoring (-1)So, x = 6 is only solution



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