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log10 |
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Answer» Suppose we have loga (b), we want to change it on exponential (e) base, then it can be written as: loga(b)=loga(e)⋅loge(b) Let's say we have, y = c ⋅ f ( x ) , where c is a constant then, y ' = c ⋅ f ' ( x ) Now, this is quite straightforward to differentiate, as log10(e) is constant, so only remaining function is loge(x) Hence, y' = log10(e) . 1/x |
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