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Long distance power transmission is carried on high voltage line. Why ? |
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Answer» When current `I` is transmitted through a power line of resistance R, Power loss `= I^(2)R`. If the power P is transmitted at voltage V, then `P= VI or I = (P//V) :.` Power loss `= P^(2)/V^(2) R` For a given power and given is line, P and R are constant. Hence, power loss `prop (1//V^(2))` It means if power is transmitted at high voltage, power loss will be small and vice-versa. |
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