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Loucus of complex number satifyingare arg[(z-5+4i)//(z+3-2i)] = - pi//4 is the are of a circle |
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Answer» whose radiusis `5sqrt(2)` `(z_(0) - (-3+2i))/(z_(0)-(5-4i))= (BD)/(AD)e^(ipi//2)=i` `RARR z_(0) +3-2i =iz_(0) - 5i -4` `rArr z_(0) = - 2-5i` `rArr " Radius" AD = |5-4i-(-2-5i)|` `= |7+i|` `= sqrt(50) = 5sqrt(2)` Length of arc `= (3)/(4)` (Perimeter of circle) `=(3)/(4)(2pixx5sqrt(2))` `= (15)/(sqrt(2))` |
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