1.

{:(" "Lt),(n rarr oo):} [ (1)/(n^(2)) sec^(2). (1)/(n^(2)) + (2)/(n^(2))sec^(2). (4)/(n^(2))+...+1/n sec^(2)1]=

Answer»

`1/2 ` SEC 1
`1/2 COSEC 1`
TAN 1
`1/2 tan 1`

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