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M and N are the mid-points of the diagonals AC and BD respectively of quadrilateral ABCD, then AB+AD+CB+CD is equal to |
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Answer» 2 MN a,b,c,d, m and n. Since, M and N are the mid-points of AC and BD. `therefore m=(a+c)/(2),n=(b+d)/(2)` Now, `AB+AD+CD+CD` `=(b-a)+(d-a)+(b-c)+(d-c)` `=2(b+d)-2)a+c)` `=2xx2n-2xx2m` `=4 (n-m)=4 NM` |
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