1.

M(OH)_x " has " a K_(sp)" of "4 xx 10 ^(-9)and its solubility is 10^(-3)M. The value of x is :

Answer»

4
1
3
2

Solution :`M(OH)_x =M^(+X)+XOH^(-) `
`"" S "" XS `
` K_(sp)=(S) (XS)^(x) , K_(sp)=S^(x+1). X^(x) `
` 4 xx 10^(-9)=X^(x). S ^(x+1)therefore x=2`


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