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मान ज्ञात कीजिए - `sin[(pi)/(3)-sin^(-1)""(-(1)/(2))]` |
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Answer» Correct Answer - 1 `sin[(pi)/(3)-sin^(-1)""(-(1)/(2))]=sin[(pi)/(3)-sin^(-1){sin(-(pi)/(6))}]` `=sin[(pi)/(3)-(-(pi)/(6))]` `=sin""((pi)/(3)+(pi)/(6))=sin""(3pi)/(6)=sin""(pi)/(2)=1 ` |
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