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Machine A has 60° phase spread and machine B has 120° phase spread. Both the machines have uniformly distributed winding. The ratio of distribution factors of machine A to machine B is ____________(a) 0.866(b) 1.1(c) 1.55(d) 1.155I got this question in a national level competition.Question is from EMF Polygon in division Synchronous Machines of Electrical Machines

Answer» RIGHT OPTION is (C) 1.55

To ELABORATE: KDA=(sinσ/2)/σ/2, σ=60° ⇒ kdA=0.9556

kdB=(sinσ/2)/σ/2, σ=120° ⇒ kdB=0.827

thus, kdA/kdB=1.155.


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