Magnesium loses electrons successively to form Mg^(+),Mg^(2+)andMg^(3+) ions . Which step will have the highest ionisation energy and why ?

Magnesium loses electrons successively to form Mg^(+),Mg^(2+)andMg^(3+

1.	Magnesium loses electrons successively to form Mg^(+),Mg^(2+)andMg^(3+) ions . Which step will have the highest ionisation energy and why ?
Answer» Solution :`UNDERSET("NEUTRAL atom")(Mg)(g) to Mg^(+) +e(I.E_(1) = X_(1))` `(Dbt: e or e^(-))` `underset("Unipositive cation")(Mg^+)to Mg^(2+) +e^(-)(I.E_(2) -X_(2))` `underset("Dipositive cation")(Mg^2+)to Mg^(3+)+e^(-)(I.E_(3) -X_(3))` (i) The third step will have the highest ionization energy. `I.E_3 gtI.E_2 gt I.E_1`. Because from a neutral gaseous atom, the electron removal is easy and less amount of energy is required. But from a dipositive cation, there will be more number of PROTONS than the electrons and there is more forces of ATTRACTION between the nucleus and electron. So the removal of electron in a dipositive cation, becomes highly difficult and more energy is required.