Magnetic field applied on a cyclotron is `0*7T` and radius of its dees is `1*8m`. What will be the energy of the emergent protons in `MeV`? Mass of proton`=1*67xx10^-27kg`.

Magnetic field applied on a cyclotron is `0*7T` and radius of its dees

1.	Magnetic field applied on a cyclotron is `07T` and radius of its dees is `18m`. What will be the energy of the emergent protons in `MeV`? Mass of proton`=1*67xx10^-27kg`.
Answer» `E=(q^2B^2r^2)/(2m)=((16xx10^-19)^2xx(07)^2xx(18)^2)/(2xx167xx10^-27)J=((16xx10^-19)^2xx(07)^2xx(18)^2)/(2xx167xx10^-27xx1*6xx10^-13)MeV` `=76MeV`

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Magnetic field applied on a cyclotron is `0*7T` and radius of its dees is `1*8m`. What will be the energy of the emergent protons in `MeV`? Mass of proton`=1*67xx10^-27kg`.

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Magnetic field applied on a cyclotron is `07T` and radius of its dees is `18m`. What will be the energy of the emergent protons in `MeV`? Mass of proton`=1*67xx10^-27kg`.