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Magnetic field at the centre of a circualr loop of area A carrying current I is B. What is the magnetic moment of this loop?A. `((BA)^(2))/(mu_(0)pi)`B. `(BAsqrtA)/(mu_(0))`C. `(BA sqrtA)/(mu_(0)pi)`D. `(2BAsqrtA)/(mu_(0)sqrtpi)` |
Answer» Correct Answer - D Let r be the radius of the circular loop. `therefore" "A=pir^(2) or r=sqrt((A)/(pi))` Magnetic field at the centre of the loop is `B=(mu_(0)I)/(2r)=(mu_(0)I)/(2sqrt((A)/(pi)))orI=(2B)/(mu_(0))sqrt((A)/(pi))` The magnetic moment of the loop is `M=IA=(2B)/(mu_(0))sqrt((A)/(pi))A=(2BAsqrtA)/(mu_(0)sqrtpi)` |
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