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Magnetic field in the cylindrical regaion with its axis passing through O varies at a constant rate `(dB)/(dt)`. A treangular imaginary loop ABC, with `AB = BC`, is lying in this region as shown in the adjacent figure. The work done to move unit positive charge from A to B along the side AB is A. `r^(2)(dB)/(dt)`B. `pir^(2)(dB)/(dt)`C. `(r^(2))/(2)(dB)/(dt)`D. `(3r^(2))/(4)(dB)/(dt)` |
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Answer» Correct Answer - C No e.m.f. will be induced in AC because electric lines of force are perpendicular to AC and e.m.f. induced in `AB=` e.m.f. induced in BC. `:.` e.m.f. induced in `AB=(1)/(2)|(dphi)/(dt)|=(1)/(2)r^(2)(dB)/(dt)` |
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