InterviewSolution
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InterviewSolution
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Magnetic moments `2.84 B.M` is given by : (At. nos. ni = 28, Ti = 22, Cr = 24, Co = 27).A. `Ni^(2+)`B. `Ti^(3+)`C. `Cr^(3+)`D. `Co^(2+)` |
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Answer» Correct Answer - A Magnetic moment `mu = sqrt( n(n+2)) BM` where `therefore 2.84= sqrt(n(n+2)) BM` `(2.84)^(2) = n(n+2)` `8=n^(2)+2n` `n^(2)+2n -8=0` `n^(2)+4n-2n-8=0` `n^(2) +4n-2n-8=0` `n(n+4)-2(n+4)=0` `n=2` ` Ni^(2+) =[Ar] 3d^(8)4s^(0)`(two uppaired electrons ) ` Ti^(3+)=[Ar] 3d^(1) 4s^(0) ` (one unpaired electron ) ` Cr^(3+) = [Ar] 3d^(3)` (three unpaired electrons ) ` Co^(2+) =[Ar] 3d^(7)4s^(0)` ( three unpaired electrons ) SO , only `Ni ^(2+)` has 2 unpaired elecrons |
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