Magnitudeof K.E. in anorbitis equal to

1.	Magnitudeof K.E. in anorbitis equal to
Answer» Halfof thepotentialenergy Twiceof thepotentialenergy One fourththepotentialenergy Noneof these SOLUTION :K.E. of `e^(-)=(1)/(2)` of P.E.K.Eis alwayspositiveor K.E. `-((1)/(2) P.E)` = - Total energyof system

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