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Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively.What is the gravitational force between them?​

Answer» GIVEN :-RADIUS = 1 mm₁ = 75 kgm₂ = 80 kgG = 6.67 × 10⁻¹¹ Nm²/kg²To Find :-Gravitational FORCE between them.Formula to be used :-Newton's Law i.e F = Gm₁m₂/r²Solution :-Putting all the values,we GETF = Gm₁m₂/r²F = 6.67 × 10⁻¹¹ × 75 × 80/1² nF = 4.002 × 10⁻⁷ NHence, the gravitational force between Mahesh and virat 4.002 × 10⁻⁷ N.Explanation:follow me


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