Make p-V equation for an adiabatic process.

1.	Make p-V equation for an adiabatic process.
Answer» Correct Answer - A::C In adiabatic process, `dQ=0` and `dW=-dU` `:.` `pdV=-C_VdT` (for `n=1`) `:.` `dT=-(pdV)/(C_V)` …(i) Also, for 1 mole of an ideal gas, `d(pV)=d(RT)` or `pdV+Vdp=RdT` or `dT=(pdV+Vdp)/(R)`…(ii) From Eqs. (i) and (ii), we get `C_VVdp+(C_V+R)pdV=0` or `C_VVdp+C_ppdV=0` Dividing this equaiton by PV, we are left with `C_V(dp)/(p)+C_p(dV)/(V)=0` or `(dp)/(p)+gamma(dV)/(V)=0` or `int(dp)/(p)+gamma int(dV)/(V)=0` or `In(p)+gamma In (V)=` constant We can write this in the form `pV^gamma=`constant

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Make p-V equation for an adiabatic process.

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