1.

Mand M/sqrt(3) are the magnetic dipole moments of the two magnets, which are joined to form a cross figure. Find the inclination of the system with the field, if their combination is suspended freely in a uniform external magnetic field B.

Answer»

`theta = 30^(@)`
`theta = 45^(@)`
`theta = 60^(@)`
`theta = 15^(@)`

Solution :TORQUE `(tau)` ACTING on magnet (1).
`""tau_(1)=MBsintheta`
`"Similarly"tau_(2)=SQRT(3)MBsintheta`
`therefore""theta=60^(@)`
But for equilibrium,`tau_(1)=tau_(2)`
`therefore ""MBsintheta=sqrt(3)MBcostheta`
`""tan theta=sqrt(3)=tan60^(@)`
`therefore""theta=60^(@)`


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