1.

Manganese forms non-stoichiometric oxides having the general formula MnO_(x). The value of x for the compound that analyzed 64% Mn. (At wt Mn=55)

Answer»

`1.16`
`1.83`
2
`1.93`

SOLUTION :`1%Mn=64=(55)/(M)XX100`
`%O=36=(16x)/(M)xx100impliesx=1.93`


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