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InterviewSolution
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many moles of lead (I1) chloride will be formedfrom a reaction between 6.5g of PbO and 32 gHCI?ofAIPMT (Prelims)-2008(1) 0.029(3) 0.333(2) 0.044(4) 0.011 |
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Answer» The equation for the reaction between PbO and HCl is as follows: PbO + 2HCl------------> PbCl2 + Cl + H2O Therefore 1 moles of PbO require 2 moles of HCl to give 1 mole of PbCl2. Calculate the reagent, between HCl and PbO, that is the limiting reagent. Pb-207.2 Cl-35.5 O-16 H-1 moles=mass/molar mass moles of PbO = 6.5/(207+16) = 6.5/223.2 = 0.029148if 1 mole = 2 moles of HClthen 0.029148= 2x0.029148= 0.058296 moles of HCl= 3.2/(1+35.5) = 3.2/36.5 = 0.08767if 2 moles of HCl= 1 mole of PbOthen 0.08767= 1x 0.8767/2 = 0.04384 Therefore PbO is the limiting reagent.Calculate moles of PbCl2 produced as follows:if 1 mole of PbO = 1 mole of PbCl2then 0.029148 will give= 1 x 0.029148 moles Therefore moles of PbCl2 produced = 0.029148 moles |
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