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Mark against the correct answer in the following:\(\int\limits_{-\pi}^\pi\,tan\,x\,dx=?\)∫ tan x dx=?, x ∈[-π,π]A. 2 B.\(\cfrac{1}{2}\) C.-2 D. 0 |
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Answer» Correct answer: D. 0 f(x)=tan x f(-x) =tan(-x) =-tan x hence the function is odd, therefore, I=0 |
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