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Answer» `CH_(3)CONH_(2) lt CH_(3)COOC_(2)H_(5) lt CH_(3)COCl` `CH_(3)COOC_(2)H_(5) lt CH_(3)COCl lt CH_(3)CONH_(2)` `CH_(3)COCl lt CH_(3)CONH_(2) lt CH_(3)COOC_(2)H_(5)` `CH_(3)COOC_(2)H_(5) lt CH_(3)CONH_(2) lt CH_(3)COCl` SOLUTION :This can be explained on the basis of basicity of leaving GROUP in each case. For acid chlorides, leaving group is `Cl^(-)` ions and for esters, leaving group is alkoxide. However, in amide, leaving group is `NH_(2)` or amine. Out of these three, `Cl^(-)` ion is weakest BASE hence acid chlorides are most reactive. But `NH_(2)` or amines are strongest bases, hence amides are least reactive
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