Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass action A(g)+B(g) harr C(g) + D(g) Q=([C][D])/([A][B]). The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q = K. For non equilibrium process, Q ne K. When Q gt K, reaction will favour backward direction and when Q lt K, it will favour forward direction. In a reaction mixture containing H_2, N_2 and NH_3 at partial pressure of 2 atm, and 3 atm respectively, the value of K_p at 725 K is 4.28 xx 10^(-5) atm^(-2). Inwhichdirectionthenetreactionwill go ? N_(2(g)) + 3H_(2(g)) harr 2NH_(3(g))

Mass action ratio or reaction quotient Q for a reaction can be calcula

1.	Mass action ratio or reaction quotient Q for a reaction can be calculated using the law of mass action A(g)+B(g) harr C(g) + D(g) Q=([C][D])/([A][B]). The value of Q decides whether the reaction is at equilibrium or not. At equilibrium, Q = K. For non equilibrium process, Q ne K. When Q gt K, reaction will favour backward direction and when Q lt K, it will favour forward direction. In a reaction mixture containing H_2, N_2 and NH_3 at partial pressure of 2 atm, and 3 atm respectively, the value of K_p at 725 K is 4.28 xx 10^(-5) atm^(-2). Inwhichdirectionthenetreactionwill go ? N_(2(g)) + 3H_(2(g)) harr 2NH_(3(g))
Answer» FORWARD Backward No net reaction DIRECTION cannot be predicted Solution :`Q_(P)=(P_(NH_(3))^(2))/(P_(H_(2))^(3) xx P_(N_(2)))=((3)^(2))/((2)^(3) xx 1)=(9)/(8) gt K_(P)` `Q gt K_(P) implies` backward direction