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Mass number of two isotopes of an element differ by 2 unit (A and A + 2) . Average atomic mass is 0.5 more than the lower mass number. What could be the ratio of the two isotopes. |
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Answer» Solution :(i) If the abundance of the ISOTOPE with MASS number A and A +2 are `n_(1) and n_(2)` respectively , then `(n_(1)A+n_(2)(A+2))/(n_(1)+n_(2))` =A+5 (II) `3:1` |
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