1.

Mass of `112 cm^(3)` of `NH_(3)` gas at S.T.P. isA. `0.085 g`B. `0.850 g`C. `8.5 g`D. `80.5 g`

Answer» Correct Answer - A
Mass of `112 cm^(3)` of `NH_(3)` at S.T.P.
`= ((112 cm^(3)))/((22400 cm^(3))) xx (17g) = 0.085 g`.


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