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Mass of a rocket is 100 kg. When 0.1 kg fuel is burnt every second, velocity of exhaust gas coming out of it is 1Km/s.Acceleration of rocket will be .......

Answer»

`1000 m//s^(2)`
`100 m//s^(2)`
`10 m//s^(2)`
`1 m//s^(2)`

Solution :`a= (F )/(m )`
`= (V_(G ) XX (dm)/(dt))/( m )`
`=(1000 xx 0.1)/( 100)`
`a= 1 m//s^(2)`


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