Mass of bigger disc having radius 2R is M. A disc of radius R is cut from bigger disc. Moment of intertia of disc about an axis passing through periphery and perpendicular to plane isA. `(27MR^(2))/8`B. `(29MR^(2))/8 `C. 3.5 MRD. 2 M`R^(2)`

Mass of bigger disc having radius 2R is M. A disc of radius R is cut f

1.	Mass of bigger disc having radius 2R is M. A disc of radius R is cut from bigger disc. Moment of intertia of disc about an axis passing through periphery and perpendicular to plane isA. `(27MR^(2))/8`B. `(29MR^(2))/8 `C. 3.5 MRD. 2 M`R^(2)`
Answer» b) Surface density of motional disc is `sigma = (M/(pi(2R)^(2)) = M/(4piR^(2))` Mass of cutting portion is `m_(1) = sigma xx piR^(2) = M/40` `I= I_(1)-I_(2)` Where, `I_(1)` = Moment of inertia of disc about given axis without cutting portion `I_(2)` = Moment of inertia due to cutting portion `I = (M(2R)^(2))/2 + M(2R)^(2) - [(m_(1)R^(2))/2 + m_(1)(3R)^(2)]` `6MR^(2) - (19MR^(2))/8 = (29MR^(2))/8`

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Mass of bigger disc having radius 2R is M. A disc of radius R is cut from bigger disc. Moment of intertia of disc about an axis passing through periphery and perpendicular to plane isA. `(27MR^(2))/8`B. `(29MR^(2))/8 `C. 3.5 MRD. 2 M`R^(2)`

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