Mass of CO_(2) is 88 g. The number of atoms of oxygen present is :

1.	Mass of CO_(2) is 88 g. The number of atoms of oxygen present is :
Answer» `2.41 XX 10^(24)` `1.2 xx 10^(23)` `1.4 xx 10^(23)` `2.41 xx 10^(23)` Solution :44.0 grams of `CO_(2)` contain oxygen ATOMS `= 2xx 6.022 xx 10^(23)` atoms 88.0 grams of `CO_(2)` contain oxygen atoms `= 2 xx 2 xx 6.022 xx 10^(23)` `=2.41 xx 10^(24)` atoms.

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