Match Column I with Column II. {:(,"Column I ",,,"Column II"),((i) ,"Equilibrium",,(a),Delta Ggt 0 ","K lt 1),((ii),"Spontaneous reaction",,(b),DeltaG=0),((iii),"Non-spontaneous reaction",,(c),Delta G ^(Θ)=0),(,,,(d),DeltaG lt 0 "," K gt 1):}

Match Column I with Column II. {:(,"Column I ",,,"Column II"),((i) ,"E

1.	Match Column I with Column II. {:(,"Column I ",,,"Column II"),((i) ,"Equilibrium",,(a),Delta Ggt 0 ","K lt 1),((ii),"Spontaneous reaction",,(b),DeltaG=0),((iii),"Non-spontaneous reaction",,(c),Delta G ^(Θ)=0),(,,,(d),DeltaG lt 0 "," K gt 1):}
Answer» Solution :(i) When reaction is in equilibrium, `DELTA G = 0 `. Hence, (i)-(b). (II) For spontaneous reaction, `Delta G lt 0 (-ve), K gt 1`. Hence (ii)-(d). (iii) For non-spontaneous reaction, `Delta G gt 0 (+ve), K lt 1`. Hence (iii) - (a).