1.

Match List I (Molecules) with List II (Bond order)and select the correctanswer using the codes.

Answer»

I - B, II - C, III - A, IV - E
I - C, II - A, III - D, IV - E
I - D, II -A, III - E, IV -C
I - C,II - B, III - E, IV -A

Solution :Bond order `= 1/2 (N_b - N_a)`
Bond order of `Li_2 = 1, N_2 = 3, Be_2 = 0, O_2 = 2`


Discussion

No Comment Found