Match List I with the List II and select the correct answer using the code given below the lists : List IList II(A)If limx→∞(x2+1x+1−ax−b)=0, then (P)a=32,b∈R(B)If limx→0(1+ax+bx2)2/x=e3, then(Q)a=1,b=−12(C)If limx→0(aex−bx)=2, then(R)a=1,b=−1(D)If limx→∞{√(x2−x+1)−ax−b}=0, then(S)a=2,b=2Which of the following is the only CORRECT combination?

Match List I with the List II and select the correct answer using the

1.	Match List I with the List II and select the correct answer using the code given below the lists : List IList II(A)If limx→∞(x2+1x+1−ax−b)=0, then (P)a=32,b∈R(B)If limx→0(1+ax+bx2)2/x=e3, then(Q)a=1,b=−12(C)If limx→0(aex−bx)=2, then(R)a=1,b=−1(D)If limx→∞{√(x2−x+1)−ax−b}=0, then(S)a=2,b=2Which of the following is the only CORRECT combination?
Answer» Match $List I$ with the $List II$ and select the correct answer using the code given below the lists : $\begin{matrix} List I & List II (A) & If lim x \to \infty (\frac{x^{2} + 1}{x + 1} - a x - b) = 0, then & (P) & a = \frac{3}{2}, b \in R (B) & If lim x \to 0 (1 + a x + b x^{2})^{2 / x} = e^{3}, then & (Q) & a = 1, b = - \frac{1}{2} (C) & If lim x \to 0 (\frac{a e^{x} - b}{x}) = 2, then & (R) & a = 1, b = - 1 (D) & If lim x \to \infty {\sqrt{(x^{2} - x + 1)} - a x - b} = 0, then & (S) & a = 2, b = 2 \end{matrix}$ Which of the following is the only CORRECT combination?