Match standard free energy of the reaction with the corresponding equi

1.	Match standard free energy of the reaction with the corresponding equilibrium constant
Answer» Solution :As we know that, `DeltaG^ө`=-RT ln K (A)If `DeltaG^ө gt 0`, i.e., `DeltaG^ө` is POSITIVE , then ln K is negative i.e., `K lt 1` (B) If `DeltaG^ө lt 0`, i.e., `DeltaG^ө` is negative then ln K is positive i.e., `K gt 1` (C) if`DeltaG^ө`=0, ln K=0, i.e., K=1

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