Match standard free energy of the reaction with thecorresponding equilibrium constant {:((i) ,DeltaG^(Θ)gt0,,(a),K gt 1),((ii),DeltaG^(Θ) lt 0,,(b) ,K=1),((iii),DeltaG^(Θ) = 0 ,,(c),K=0),(,,,(d),K lt 1),(,,,,):}

Match standard free energy of the reaction with thecorresponding equil

1.	Match standard free energy of the reaction with thecorresponding equilibrium constant {:((i) ,DeltaG^(Θ)gt0,,(a),K gt 1),((ii),DeltaG^(Θ) lt 0,,(b) ,K=1),((iii),DeltaG^(Θ) = 0 ,,(c),K=0),(,,,(d),K lt 1),(,,,,):}
Answer» Solution :`DeltaG^(@)` = - RT ln K (i) If `DeltaG^(@) GT 0`, i.e., `Delta^(@)` is +ve, then ln K is -ve, i.e., `K lt 1` . HENCE, (i)-(d). (ii) If `DeltaG^(@) lt 0`, i.e., `DeltaG^(@)` is -ve, then ln K is +ve, i.e., `K gt 1`. Hence, (ii) -(a). (iii) If `DeltaG^(@)= 0`, lnK = 1 , i.e., K = 1. Hence, (iii)-(b).