1.

Match the bond enthalpies given in column II with the molecules given in column I and mark the appropriate choice. {:(,"Column I",,"Column II "),((A),"Hydrogen "(H_(2)),(i),498.0 " kJ mol"^(-1)),((B),"Oxygen"(O_(2)),(ii),946.0" kJ mol"^(-1)),((C),"Nitrogen"(N_(2)),(iii),435.8 " kJ mol"^(-1)):}

Answer»

`(A)to(i), (B)to(ii), (C) to (III)`
`(A) to (iii), (B) to (ii), (C ) to (i) `
`(A) to (i), (B) to (iii), (C ) to (ii)`
`(A) to (iii), (B) to (i), (C ) to (ii)`

SOLUTION :The order of bond enthalpies of the bonds is given asBond order `propto` Bond enthalpy
Hence, SINGLE bond enthalpy ` lt` double bond enthalpy ` lt` triple bond enthalpy
`H - H lt O = O lt N -= N`


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