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Match the following. |
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Answer» A. Number of moles of `CO_(2)` molecule `=("Weight in gram of" CO_(2))/("molecular weight of " CO_(2))=(88)/(44)=2` mol B. 1 mole of a substance `=N_(A)` molecules `=6.022xx10^(23)` molecuels =Avogadro number `=6.022xx10^(23)` molecuels of `H_(2)O=1` mol C. 22.4L of `O_(2)` at StP=1 mol D. Number of moles of 96g of `O_(2)=(96)/(32)"mol"=3"mol"` E. 1 mole of any gas=Avogadro number `=6.022xx10^(23)` molecuels |
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